Power Tower 3 and Up Arrows
3↑3 or 3↑13
= 33
= 3×3×3
= 273↑↑3 or 3↑23
= 3↑3↑3
= 333 , with 3 floors of 3's
= 327
= 7,625,597,484,987
3↑↑↑3 or 3↑33
= 3↑↑3↑↑3
= 3↑↑(333 )
= 3↑3↑ ... 3↑3, with 333 of 3's
= 33..33 } 333 floors of 3's
= 33..33 } 7,625,597,484,987 floors of 3's
3↑↑↑↑3 or 3↑43 (= G(1), first layer of Graham's number)
= 3↑↑↑3↑↑↑3
= 3↑↑3↑↑ ... 3↑↑3 , with 3↑↑↑3 or 3↑33 of 3's
= 33..33 } 33..33 } ... 33..33 } 33..33 } 333 , with 3↑↑↑3 or 3↑33 of power tower 33..33 's
3↑↑↑↑↑3 or 3↑53
= 3↑↑↑↑3↑↑↑↑3
= 3↑↑↑3↑↑↑ ... 3↑↑↑3, with 3↑↑↑↑3 of 3's
= L1 ⤋ L2 ⤋ L3 ⤋ ... (with L1 of L's), where
- L1 = 3↑↑↑↑3; and
- L2 = 33..33 } 33..33 } ... 33..33 } 33..33 } 333 , with L1 of power tower 33..33 's;
- and so on.
- ⤋denotes left value equals numbers of power tower 33..33 at its right.
33..33 } 33..33 } ... 33..33 } 33..33 } 333 , with 3↑↑↑3 or 3↑33 of power tower 33..33 's
_____________________________/\_____________________________
/ \
33..33 } 33..33 } 33..33 } 33..33 } ... 33..33 } 33..33 } 33..33 } 33..33 } 333
_____________________________/\_____________________________
/ \
33..33 } 33..33 } 33..33 } 33..33 } ... 33..33 } 33..33 } 33..33 } 33..33 } 333
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_____________________________/\_____________________________
/ \
33..33 } 33..33 } 33..33 } 33..33 } ... 33..33 } 33..33 } 33..33 } 33..33 } 333
_____________________________/\_____________________________
/ \
33..33 } 33..33 } 33..33 } 33..33 } ... 33..33 } 33..33 } 33..33 } 33..33 } 333
, with 3↑↑↑↑3 layers of _____________________________/\_____________________________
/ \
, where number of power tower 33..33's in any layer = value of its upper layer
3↑↑↑↑↑↑3 or 3↑63
= 3↑↑↑↑↑3↑↑↑↑↑3
= 3↑↑↑↑3↑↑↑↑...3↑↑↑↑3, with 3↑↑↑↑↑3 or 3↑53 of 3's
= ≡ } ≡ } ≡ } ... ≡ } ≡ } 3↑53 , with 3↑↑↑↑↑3 or 3↑53 of ≡ 's, where ≡ denotes the tower similar to 3↑53 above (with the number of layers of any ≡ equals value of the ≡ at its right side)
3↑↑↑↑↑↑↑3 or 3↑73
= 3↑↑↑↑↑↑3↑↑↑↑↑↑3
= 3↑↑↑↑↑3↑↑↑↑↑...3↑↑↑↑↑3, with 3↑↑↑↑↑↑3 or 3↑63 of 3's
= L1 ⤋ L2 ⤋ L3 ⤋ ... (with L1 of L's), where
- L1 = 3↑63; and
- L2 = ≡ } ≡ } ≡ } ... ≡ } ≡ } 3↑53 , with L1 of ≡ 's;
- and so on.
As you can see, 8 up arrows will be in the form of ≡ } ≡ } ≡ } ... ≡ } ≡ } 3↑73; then 9 up arrows will be in the form of L1 ⤋ L2 ⤋ L3 ⤋ ... ; and so on. In short, they are alternating between ≡ } ≡ } ≡ } ... ≡ } ≡ and L1 ⤋ L2 ⤋ L3 ⤋ ...
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3↑G(1)3 (= G(2), 2nd layer of Graham's number)
= 3↑↑↑ ... ↑↑↑3, with G(1) of ↑ 's
3↑G(2)3 (= G(3), 3rd layer of Graham's number)
= 3↑↑↑ ... ↑↑↑3, with G(2) of ↑ 's
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3↑G(62)3 (= G(63), 63rd layer of Graham's number)
= 3↑↑↑ ... ↑↑↑3, with G(62) of ↑ 's
3↑G(63)3 (= G(64), Graham's number)
= 3↑↑↑ ... ↑↑↑3, with G(63) of ↑ 's
My brain is starting to hurt....
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